DIY Builds
DIY Builds
Photo: Subhajit Biswas
So, to answer your question, “yes, the 2x4 will sag over a 16' span AND the compression added by the wire will not save it.”
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Learn More »Wow, this is really interesting. I’m not sure I understand the problem, (and I’m suppose to know this stuff.) I hope it’s just terminology... Seldom is a member only in “tension” or “compression “. (I can only think of some chords in a truss...maybe.) So, when your horizontal 2x4 member sags (bends), it’s in tension on the bottom and compression on top. Then, when you tighten the wires, you’ll induce more compression into the 2x4. This is what we call “double bending” and often causes buckling. We can calculate this buckling by knowing the load (compression load) and the span...we call this the “slenderness ratio”. Every material, (wood, concrete,steel, jello, etc.) has an allowable slenderness ratio based on the strain (not stress) of the load on the material and the span. (This is how they calculate allowable loads on columns to keep them from bending.) So, the more you tighten the wires, the more the 2x4 will “tend” to bend and must resist the load or it will buckle. Because the slenderness ratio is based on the skinniest side of the 2x4, it helps to add a 2x4 in the opposite direction. (It has nothing to do with the flanges on a steel beam, like @isherwood says.) So, to answer your question, “yes, the 2x4 will sag over a 16’ span AND the compression added by the wire will not save it.” Whew...that was hard to explain...but the more compression you add to keep it from sagging, the more you’ll cause it to buckle...until you add another member perpendicular to the 2x4. By the way, if you try to use the 2x4 member, make sure you tighten the wires evenly or you’ll introduce “twist” to the 2x4, and that is way too difficult to calculate...but will cause failure even quicker. I don’t know how many 16’ spans you have, but after about 2 spans, you’ll use a lot less lumber by using either of your 2 options.
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